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tps53513 FB引脚计算疑问

你好,我看数据手册对FB部分的计算不太理解,能不能帮忙介绍下,谢谢!

  • HI

        见计算如下:

       

       R1是高边电阻,R2是低边电阻, Vout是输出电压,Vfb是反馈基准电压,忽略流进FB的电流,所以:

       (Vout-Vfb)/R1= Vfb/R2    

       R1=(Vout-Vfb) *R2/Vfb      Vfb=0.6V,  Vout是输出电压,这里是设置为1.2V输出, R1这里取的是10kohm.

       代入就是上面.

       

      V

  • 从原理框图可以看出,内部基准为0.6V,因为只要两个电阻分压,让FB端电压为0.6V即可,就是一个分压的计算而已。