This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

数字移相全桥PWM脉冲的问题

在数字电源库PWM_PSFB_PCMC_Cnf.c文件中,因为需要四路驱动信号,左桥臂代码很好看懂,右桥臂的代码是这样的

(*ePWM[n+1])是Epwm2Regs寄存器。

//Time Base SubModule Register
(*ePWM[n+1]).TBCTL.bit.PRDLD = TB_SHADOW;
(*ePWM[n+1]).TBPRD = period-1;
(*ePWM[n+1]).TBPHS.half.TBPHS = 0;
(*ePWM[n+1]).TBCTR = 0;

(*ePWM[n+1]).TBCTL.bit.CTRMODE = TB_COUNT_UP;
(*ePWM[n+1]).TBCTL.bit.PHSEN = TB_ENABLE;
(*ePWM[n+1]).TBCTL.bit.SYNCOSEL = TB_SYNC_IN; // Sync "flow through" mode
(*ePWM[n+1]).TBCTL.bit.HSPCLKDIV = TB_DIV1;
(*ePWM[n+1]).TBCTL.bit.CLKDIV = TB_DIV1;

// Counter compare submodule registers
(*ePWM[n+1]).CMPA.half.CMPA = period + 10; // Initial value
(*ePWM[n+1]).CMPB = 20; // Initial value
(*ePWM[n+1]).CMPCTL.bit.LOADAMODE = CC_CTR_ZERO;
(*ePWM[n+1]).CMPCTL.bit.SHDWAMODE = CC_SHADOW;
(*ePWM[n+1]).CMPCTL.bit.LOADBMODE = CC_CTR_ZERO;
(*ePWM[n+1]).CMPCTL.bit.SHDWBMODE = CC_SHADOW;

// Action Qualifier SubModule Registers
(*ePWM[n+1]).AQCTLA.bit.CAU = AQ_SET;
(*ePWM[n+1]).AQCTLA.bit.CBU = AQ_CLEAR;
(*ePWM[n+1]).AQCTLA.bit.ZRO = AQ_CLEAR;
(*ePWM[n+1]).AQCTLA.bit.PRD = AQ_CLEAR;

(*ePWM[n+1]).AQCTLB.bit.CBU = AQ_SET;
(*ePWM[n+1]).AQCTLB.bit.CAU = AQ_CLEAR;
(*ePWM[n+1]).AQCTLB.bit.ZRO = AQ_CLEAR;
(*ePWM[n+1]).AQCTLB.bit.PRD = AQ_CLEAR;


不明白为什么要把比较值是周期加上10,以及后面的脉冲是什么样的?有点搞不明白,希望可以解答,谢谢。