28035的LIN模块，用作SCI兼容模式，参考controlsuit的几个例子，写了一段简单的代码，结果出现一个问题：如果利用缓存模式，填满LinaRegs.LINTD0和LinaRegs.LINTD1 共8个 char，然后不管使用loopback还是对外部发送， 结果总是丢失 LinaRegs.LINTD0.bit.TD0 这个char，实在搞不懂怎么回事。
代码如下（仅对寄存器初始化，然后填充TD缓存） ：
void Init(void)
{
EALLOW; // This is needed to write to EALLOW protected registers
LinaRegs.SCIGCR0.bit.RESET = 0; //Into reset
LinaRegs.SCIGCR0.bit.RESET = 1; //Out of reset
LinaRegs.SCIGCR1.bit.SWnRST = 0; //Into software reset
//SCI Configurations
LinaRegs.SCIGCR1.bit.COMMMODE = 0; //Idle-Line Mode
LinaRegs.SCIGCR1.bit.TIMINGMODE = 1; //Asynchronous Timing
LinaRegs.SCIGCR1.bit.PARITYENA = 1; //Parity Check
LinaRegs.SCIGCR1.bit.PARITY = 1; //Even Parity
LinaRegs.SCIGCR1.bit.STOP = 0; //One Stop Bit
LinaRegs.SCIGCR1.bit.CLK_MASTER = 1; //Enable SCI Clock
LinaRegs.SCIGCR1.bit.LINMODE = 0; //SCI Mode
LinaRegs.SCIGCR1.bit.SLEEP = 0; //Ensure Out of Sleep
LinaRegs.SCIGCR1.bit.MBUFMODE = 1; //Buffered Mode
LinaRegs.SCIGCR1.bit.LOOPBACK = 1; //Internal Loopback
LinaRegs.SCIGCR1.bit.CONT = 1; //Continue on Suspend
LinaRegs.SCIGCR1.bit.RXENA = 1; //Enable RX
LinaRegs.SCIGCR1.bit.TXENA = 1; //Enable TX
//Ensure IODFT is disabled
LinaRegs.IODFTCTRL.bit.IODFTENA = 0x0;
//Set transmission length
LinaRegs.SCIFORMAT.bit.CHAR = 7; //Eight bits
LinaRegs.SCIFORMAT.bit.LENGTH = 7;
//Set baudrate
LinaRegs.BRSR.bit.SCI_LIN_PSL =194; //9600 bps for SYSCLKOUT = 60 MHz
LinaRegs.BRSR.bit.M =5;
LinaRegs.SCIGCR1.bit.SWnRST = 1; //bring out of software reset
EDIS;
while(LinaRegs.SCIFLR.bit.IDLE == 1);
LinaRegs.LINTD1.bit.TD7 = 0x08;
LinaRegs.LINTD1.bit.TD6 = 0x07;
LinaRegs.LINTD1.bit.TD5 = 0x06;
LinaRegs.LINTD1.bit.TD4 = 0x05;
LinaRegs.LINTD0.bit.TD3 = 0x04;
LinaRegs.LINTD0.bit.TD2 = 0x03;
LinaRegs.LINTD0.bit.TD1 = 0x02;
LinaRegs.LINTD0.bit.TD0 = 0x01;
}
然后，从监视器看到的情况是这样的，TD是对的，RD就是 RD0 那里总是收不到数据，如果是对外发送，用示波器观察，也是发少一个数。
请教究竟是怎么回事？
